13x=50-4.9(x)^2

Solution for 13x=50-4.9(x)^2 equation:

13x=50-4.9(x)^2

We move all terms to the left:

13x-(50-4.9(x)^2)=0

determiningTheFunctionDomain
-(50-4.9x^2)+13x=0

We get rid of parentheses

4.9x^2+13x-50=0

a = 4.9; b = 13; c = -50;
Δ = b2-4ac
Δ = 132-4·4.9·(-50)
Δ = 1149
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{1149}}{2*4.9}=\frac{-13-\sqrt{1149}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{1149}}{2*4.9}=\frac{-13+\sqrt{1149}}{9.8}
$